Question 15 A vertical pole of a length 6 m casts a shadow 4m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower.
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Length of the vertical pole = 6m (Given) Length of the shadow of the pole = 4 m (Given) Let Height of tower = h m Length of shadow of the tower = 28 m (Given) In ΔABCandΔDEF, ∠C=∠E(angularelevation) ∠B=∠F=90∘ ∴ΔABC∼ΔDFE (By AAA similarity criterion) ∴ABDF=BCEF (If two triangles are similar then their corresponding sides are proportional.) ∴6h=428 ⇒h=6×284 ⇒h=6×7 ⇒h=42m Hence, the height of the tower is 42 m.