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A vertical spring with force constant k is fixed on a table.A ball of mass m at a height h above the free upper end of the spring falls vertically on the spring,so that the spring is compressed by a distance d.What is the net work done in the process?

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Q. A vertical spring with force constant k is fixed on a table. A ball of mass m at a height h above the free upper end of the spring falls vertically on the spring so that the spring is compressed by a distance d. The net work done in the process is

M

is allowed to fall on a pedestal fixed on the top of a vertical spring. If the height of the mass was

H

from the pedestal and the compression of the spring is

d

then the force constant of the spring is given by:

Q. A ball of mass

m

is attached to the lower end of a light vertical spring of force constant

k

. The upper end of the spring is fixed. The ball is released from rest with the spring is at its natural length. The ball comes to rest momentarily after descending through a distance

y

. At this position, acceleration of the ball is

Q. A ball of mass

m

is attached to the lower end of a light vertical spring of force constant

k

. The upper end of the spring is fixed. The ball is released from rest with the spring at its normal (unstretched) length, and comes to rest again after descending through a distance

x

. Given acceleration due to gravity

= g

.

m

hung on a vertical ideal spring (of spring constant

k

) is initially held at its highest position above equilibrium such that the spring is compressed by

x_{1}

. When released, the mass falls through a distance

2 h

such that the lowest point it reaches is when the spring is stretched by

x_{2}

.
Based on this, what is

x_{2} - x_{1}

? Neglect energy loss through friction or air resistance.

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