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Standard XII

Chemistry

Raoult's Law

A very dilute...

Question

A very diluted saturated solution of a sparingly soluble salt $X_{3} Y_{4}$ has vapour pressure of 20 mm Hg at temperature T, while pure water exerts a pressure of 20.0126 mm Hg at the same temperature. calculate molality (m) at temperature T:

6.3 \times 10^{- 4}

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3.5 \times 10^{- 2}

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5 \times 10^{- 3}

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None of these

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Solution

The correct option is D $5 \times 10^{- 3}$
$m \times i = \frac{P^{\circ} - P}{P} \times \frac{1000}{M_{s o l v e n t}};$

$7 m = \frac{(20.0126 \times 20) \times 1000}{20 \times 18}$

$m = 5 \times 10^{- 3}$

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A very diluted saturated solution of a sparingly soluble salt X3Y4 has vapour pressure of 20 mm Hg at temperature T, while pure water exerts a pressure of 20.0126 mm Hg at the same temperature. calculate molality (m) at temperature T:

The correct option is D 5×10−3m×i=P∘−PP×1000Msolvent;7m=(20.0126×20)×100020×18m=5×10−3

A very diluted saturated solution of a sparingly soluble salt $X_{3} Y_{4}$ has vapour pressure of 20 mm Hg at temperature T, while pure water exerts a pressure of 20.0126 mm Hg at the same temperature. calculate molality (m) at temperature T:

The correct option is D $5 \times 10^{- 3}$
$m \times i = \frac{P^{\circ} - P}{P} \times \frac{1000}{M_{s o l v e n t}};$

$7 m = \frac{(20.0126 \times 20) \times 1000}{20 \times 18}$

$m = 5 \times 10^{- 3}$