A very good evening to RESPECTED EXPERTS -A GAS EXPANDS ISOTHERMALLY from 10 dm3 to 20 dm3 nbsp-at 27 degree celsius nbsp-and work obtained is 4-620 kj- calculate the number of mols of the gas- nbsp-

Dear Student, Work done in isothermal expansion is given by: w #160;= #160;nRT #160;lnVfVi w = work done = 4.620 kJ = 4620 J n = number of moles = ? R = ...

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Standard XII

Chemistry

Work done in Isothermal Irreversible Process

a very good e...

Question

a very good evening to RESPECTED EXPERTS
A GAS EXPANDS ISOTHERMALLY from 10 dm3 to 20 dm3 at 27 degree celsius and work obtained is 4.620 kj. calculate the number of mols of the gas.

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Solution

Dear Student,

Work done in isothermal expansion is given by:
$w = n R T \ln \frac{V_{f}}{V_{i}}$
w = work done = 4.620 kJ = 4620 J
n = number of moles = ?
R = gas constant = 8.314 J/K.mol
T = temperature = 27 ^oC = 273+27 = 300 K
V_f= final volume = 20 dm³
V_i= initial volume = 10 dm³
$w = n R T \ln \frac{V_{f}}{V_{i}}$
$4620 = n (8.314) (300) \ln \frac{20}{10}$
$4620 = n (8.314) (300) \ln (2)$
n = 2.673
number of moles of gas = 2.673 mol

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a very good evening to RESPECTED EXPERTS A GAS EXPANDS ISOTHERMALLY from 10 dm3 to 20 dm3 at 27 degree celsius and work obtained is 4.620 kj. calculate the number of mols of the gas.

a very good evening to RESPECTED EXPERTS
A GAS EXPANDS ISOTHERMALLY from 10 dm3 to 20 dm3 at 27 degree celsius and work obtained is 4.620 kj. calculate the number of mols of the gas.