Question

A very long wire carrying a current $I=5.0A$ is bent at right angles. The magnetic induction (in $muT$) at a point lying on a perpendicular to the wire, drawn through the point of bending, at a distance $l=35cm$ from it is

Answer 1

$\overrightarrow{B_0}=\overrightarrow{B_1}+\overrightarrow{B_2}$
$\overrightarrow{B_1},\overrightarrow{B_2}$ are equal in magnitude and perpendicular to each other. their magnitude = $\frac{{\mu }_{0}i}{4\pi l}$
or, $|\overrightarrow{B_0}|=\frac{{\mu }_{0}i}{4\pi l}\sqrt{2}=2.0\mu T$