A vessel A has volume V and a vessel B has volume 2V. Both contain some water which has a constant volume. The pressure in the space above water is $p_{a}$ for vessel A and $p_{b}$ for vessel B.

p_{a} = p_{b}

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p_{a} = 2 p_{b}

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p_{b} = 2 p_{a}

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p_{b} = 4 p_{a}

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Solution

The correct option is A $p_{a} = p_{b}$
The saturation vapour pressure depends on the temperature only for same liquid.

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Figure shows two vessels A and B with rigid walls containing ideal gases. The pressure, temperature and the volume are $p_{A}, T_{A}$ , V in the vessel A and $p_{B}, T_{B}$ , V in the vessel B. The vessels are now connected through a small tube. Show that the pressure p and the temperature T satisfy $\frac{p}{T} = \frac{1}{2} (\frac{p_{A}}{T_{A}} + \frac{p_{B}}{T_{B}})$ when equilibrium is achieved.