Question

A vessel at $100K$ contains $C{O}_2$ with a pressure of $0.5atm$. Some of the $C{O}_2$ is converted into $CO$ on the addition of graphite.

If the value of $K_p$ is x, Find 10x.Total pressure at equilibrium is $0.8atm$.

Answer 1

$C{O}_2\left(g\right)+C\left(s\right)\rightleftharpoons 2CO\left(g\right)$

Initial pressure $0.500$
Final pressure $(0.5-P)02P$

Total pressure at equilibrium $=0.8=0.5-P+2P$

$\therefore P=0.3atm$

$\therefore P_{C{O}_2}^{\prime }=0.5-0.3=0.2atm$
$P_{CO}^{\prime }=2\times \left(0.3\right)=0.6atm$

$\therefore K_p=\frac{{\left(P_{CO}^{\prime }\right)}^2}{P_{C{O}_2}^{\prime }}=\frac{{\left(0.6\right)}^2}{\left(0.2\right)}=1.8atm$

$x=1.8$

$\therefore 10x=18$