You visited us 1 times! Enjoying our articles? Unlock Full Access!

Characteristics of Equilibrium Constant

A vessel; at ...

Question

A vessel; at 1000 K contains $C O_{2}$ with a pressure of 0.5 atm. Some of the $C O_{2}$ is converted into CO on the addition of graphite. If the total pressure at equilibrium is 0.8 atm, the value of K is:

1.8 atm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3 atm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.3 atm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.18 atm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 1.8 atm
$C O_{2} + C_{g r a p h i t e} ⇌ 2 C O$
$P_{i n i t i a l} 0.5 a t m 0$
$P_{f i n a l} (0.5 - x) a t m 2 x a t m$
$Total P at equilibrium 0.5 - x + 2 x = 0.5 + x a t m$
$0.8 = 0.5 + x$
$∴ x = 0.8 - 0.5 = 0.3 a t m$
Now $K_{p} = \frac{(P_{C O})^{2}}{P_{C O_{2}}}$
$K_{p} = \frac{(2 \times 0.3)^{2}}{(0.5 - 0.3)} = \frac{(0.6)^{2}}{(0.2)} = 1.8 a t m$

Suggest Corrections

Similar questions

Q. A vessel; at 1000 K contains

C O_{2}

with a pressure of 0.5 atm. Some of the

C O_{2}

is converted into CO on the addition of graphite. If the total pressure at equilibrium is 0.8 atm, the value of K is:

Q. A vessel at 1000 K contains

{C O}_{2}

with a pressure of

0.5

atm. Some of the

{C O}_{2}

are converted into

C O

on the addition of graphite. If the total pressure at equilibrium is

0.8

atm the value of

K

is:

Q. A vessel at 100K contains

{C O}_{2}

with a pressure of 0.5 atm. Some of the

{C O}_{2}

is converted into CO on addition of graphite, calculate the value of K, if total pressure at equilibrium is 0.8 atm.

Q. A vessel at

1000 K

contains

C O_{2}

with a pressure of

0.5 a t m

. Some of

C O_{2}

is converted into

C O

on addition of graphite. The value of

^{'} K_{p}^{'}

at equilibrium when total pressure is

0.8 a t m

will be ?

Q. A vessel; at 1000 K contains

C O_{2}

with a pressure of 0.5 atm. Some of the

C O_{2}

is converted into CO on the addition of graphite. If the total pressure at equilibrium is 0.8 atm, the value of K is:

Join BYJU'S Learning Program

Explore more

Characteristics of Equilibrium Constant

Standard XI Chemistry

Join BYJU'S Learning Program

A vessel; at 1000 K contains CO2 with a pressure of 0.5 atm. Some of the CO2 is converted into CO on the addition of graphite. If the total pressure at equilibrium is 0.8 atm, the value of K is:

The correct option is A 1.8 atm CO2+Cgraphite⇌2CO Pinitial 0.5 atm 0 Pfinal (0.5−x)atm 2x atm Total P at equilibrium 0.5−x+2x=0.5+x atm 0.8=0.5+x ∴x=0.8−0.5=0.3 atm Now Kp=(PCO)2PCO2 Kp=(2×0.3)2(0.5−0.3)=(0.6)2(0.2)=1.8 atm

A vessel; at 1000 K contains $C O_{2}$ with a pressure of 0.5 atm. Some of the $C O_{2}$ is converted into CO on the addition of graphite. If the total pressure at equilibrium is 0.8 atm, the value of K is: