A vessel containing 9 litres of an ideal gas at 760 mm pressure is connected to an evacuated 9 litre vessel. The resultant pressure is

380 mm

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760 mm

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190 mm

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1140 mm

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Solution

The correct option is A 380 mm
By ideal gas equation, PV = nRT
now we are given that T is constant
We observe that n $α$ PV
also number of moles depend on mass so number of moles will remain conserved
so, product PV will remain conserved because PV is proportional to "n"
$P_{1} V_{1} = P_{2} V_{2}$
here $P_{1}$ = 760
$V_{1}$ = 9 ltr
$V_{2}$ = 9 + 9 = 18 ltr
solving, we get $P_{2}$ = 380 mm of mercury

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