A vessel contains 1.5L of gas at a particular temperature and 60 cm Hg pressure. Keeping the temperature constant if the pressure of air is increased to 80 cm Hg, then what will be the volume of that gas?
1.125 L
As the temperature is constant, here Boyle's law is applied,
According to Boyle's law: P1V1=P2V2⇒V2=P1V1P2
Here P1=60cm Hg : P2=80cm Hg V1=1.5L
⇒V2=60×1.580
⇒V2=1.125L
Therefore, the volume of air at 80 cm Hg= 1.125L