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Question

A vessel contains 1.60 g of oxygen and 2.80 g of nitrogen. The temperature is maintained at 300 K and the volume of the vessel is 0.166 m3. Find the pressure of the mixture.

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Solution

Here, V = 0.166 m3T=300 KMass of O2=1.60 gMO=32 gnO=1.6032=0.05Mass of N2=2.80 gMN=28 gnN=2.8028=0.1Partial pressure of O2 is given byPO=nORTV=0.05×8.3×3000.166=750Partial pressure of N2 is given byPN=nNRTV=0.1×8.3×3000.166=1500Total pressure is sum of the partial pressures.P=PN+PO=750+1500=2250 Pa

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