Question

A vessel contains 1 mole of an ideal monoatomic gas. The coefficient of volume expansion of the gas is $\alpha$. 2 moles of a diatmoic; ideal gas is then introduced into the same vessel. The coefficient of the volume expansion of the mixture will be

• A. $3\alpha /2$
• B. $2\alpha /3$
• C. $\alpha$
• D. $\alpha /3$

Answer 1

Answer: (C)

$\alpha$

The volume coefficient of gas is given by,
${\alpha }_V={\left(\frac{1}{V}\frac{\partial V}{\partial T}\right)}_p$
From the above equation it can be seen that it is independent of the number of moles,