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Byju's Answer

Standard XII

Physics

Ideal Gas Equation from KTG

A vessel cont...

Question

A vessel contains $1$ mole of $O_{2}$ gas (molar mass $32$ ) at a temperature $T$ . The pressure of the gas is $P$ . An identical vessel containing one mole of $H e$ gas (molar mass $4$ ) at a temperature $2 T$ has a pressure of

P/8

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Solution

The correct option is C
2P

For a gas, $P V = n R T$ . Hence

$(P)_{O_{2}} = \frac{(1 m o l e) R T}{V}$

and $(P)_{H e} = \frac{(1 m o l e) R (2 T)}{V}$

$∴ \frac{(P)_{H e}}{(P)_{O_{2}}} = 2$ or $(P)_{H e} = 2 (P)_{O_{2}}$

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A vessel contains 1 mole of O2 gas (molar mass 32) at a temperature T. The pressure of the gas is P. An identical vessel containing one mole of He gas (molar mass 4) at a temperature 2T has a pressure of

The correct option is C 2P For a gas, PV = nRT. Hence (P)O2 = (1mole)RTV and (P)He = (1mole)R(2T)V ∴ (P)He(P)O2 = 2 or (P)He = 2(P)O2

A vessel contains $1$ mole of $O_{2}$ gas (molar mass $32$ ) at a temperature $T$ . The pressure of the gas is $P$ . An identical vessel containing one mole of $H e$ gas (molar mass $4$ ) at a temperature $2 T$ has a pressure of

The correct option is C
2P

For a gas, $P V = n R T$ . Hence

$(P)_{O_{2}} = \frac{(1 m o l e) R T}{V}$

and $(P)_{H e} = \frac{(1 m o l e) R (2 T)}{V}$

$∴ \frac{(P)_{H e}}{(P)_{O_{2}}} = 2$ or $(P)_{H e} = 2 (P)_{O_{2}}$