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Ideal Gas Equation

A vessel cont...

Question

A vessel contains $1$ mole of $O_{2}$ gas (molar mass $= 32$ ) at temperature T. The pressure of the gas is $P$ . An identical vessel containing one mole of He gas (molar mass $= 4$ ) at a temperature $2 T$ , has a pressure of

P / 8

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P

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2 P

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8 P

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Solution

The correct option is B $2 P$
We know that:
$P V = n R T$
Here, $P_{1} = P, V_{1} = V_{2} = V$ (as identical vessel volume V is same for both gas), $T_{1} = T, T_{2} = 2 T, n_{1} = n_{2} = 1, P_{2} = ?$
Thus, $\frac{P_{2}}{P_{1}} = \frac{T_{2}}{T_{1}}$
or $\frac{P_{2}}{P} = \frac{2 T}{T} \Rightarrow P_{2} = 2 P$

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A vessel contains 1 mole of O2 gas (molar mass=32) at temperature T. The pressure of the gas is P. An identical vessel containing one mole of He gas (molar mass=4) at a temperature 2T, has a pressure of

The correct option is B 2PWe know that:PV=nRTHere, P1=P,V1=V2=V (as identical vessel volume V is same for both gas), T1=T,T2=2T,n1=n2=1,P2=? Thus, P2P1=T2T1or P2P=2TT⇒P2=2P

A vessel contains $1$ mole of $O_{2}$ gas (molar mass $= 32$ ) at temperature T. The pressure of the gas is $P$ . An identical vessel containing one mole of He gas (molar mass $= 4$ ) at a temperature $2 T$ , has a pressure of