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Gases in Liquids

A vessel cont...

Question

A vessel contains equal amount of oxygen and carbon monoxide at 10 atm.Calculate the partial pressure of $O_{2}$ under similar condition.

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Solution

no. of moles of $O_{2}$ = $\frac{g i v e n m a s s}{m o l a r m a s s}$ = $\frac{x}{32}$
no. of moles of $C O_{2}$ = $\frac{g i v e n m a s s}{m o l a r m a s s}$ = $\frac{x}{44}$
Mole fraction of $O_{2}$ = $\frac{n o . o f m o l e s o f O_{2}}{n o . o f m o l e s o f O_{2} + n o . o f m o l e s o f C O_{2}}$ = $\frac{\frac{x}{32}}{\frac{x}{32} + \frac{x}{44}}$ = $\frac{\frac{x}{32}}{\frac{76 x}{1408}}$ = 0.5
The partial pressure of an individual gas is equal to the total pressure multiplied by the mole fraction of that gas.
So, Partial pressure of $O_{2}$ = 10 $\times$ 0.5 = 5 atm

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