A vessel contains water up to a height of $1.5m$. Taking the density of water ${10}^{3}kg{m}^{-3}$, acceleration due to gravity $9.8m{s}^{-2}$ and area of base of vessel $100c{m}^2$, calculate : (a) the pressure and (b) the thrust at the base vessel.

The correct options are:
(A) The pressure= $1.47\times {10}^4$ $N$ $m^{-2}$
(B) The trust at the base level$=147N$
We know that,
Pressure $=\rho gh$
where $\rho =$density of water
$g=$acceleration due to gravity

$h=$height of water column
$P={10}^3\times 9.8\times 1.5=1.47\times {10}^{4}N{m}^2$
Upthrust = Force exerted = Pressure $\times$ Area
$\Rightarrow$ Upthrust = $1.47\times {10}^{4}N{m}^2\times 100\times {10}^{-4}m=147N$