A vessel contains water up to a height of $20 c m$ and above it an oil up to another $20 c m$ . The refractive indices of the water and the oil are $1.33$ and $1.30$ respectively. Find the apparent depth of the vessel when viewed from above.

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Solution

$μ$ = $\frac{R e a l d e p t h}{A p p a r e n t d e p t h}$

$h_{1}$ =real depth 1
$h_{2}$ =real depth 2
h'= apparent depth
h'= $\frac{h_{1}}{μ_{1}}$ + $\frac{h_{2}}{μ_{2}}$
h'= $\frac{20}{1.33}$ + $\frac{20}{1.30}$
= 15.03+15.38
= 30.41 cm.

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A vessel contains water up to a height of 20 cm and above it an oil up to another 20 cm. The refractive indices of the water and the oil are 1.33 and 1.30 respectively. Find the apparent depth of the vessel when viewed from above.

μ=RealdepthApparentdepthh1=real depth 1h2=real depth 2h'= apparent depthh'= h1μ1+h2μ2h'= 201.33+201.30= 15.03+15.38= 30.41 cm.

A vessel contains water up to a height of $20 c m$ and above it an oil up to another $20 c m$ . The refractive indices of the water and the oil are $1.33$ and $1.30$ respectively. Find the apparent depth of the vessel when viewed from above.

$μ$ = $\frac{R e a l d e p t h}{A p p a r e n t d e p t h}$

$h_{1}$ =real depth 1
$h_{2}$ =real depth 2
h'= apparent depth
h'= $\frac{h_{1}}{μ_{1}}$ + $\frac{h_{2}}{μ_{2}}$
h'= $\frac{20}{1.33}$ + $\frac{20}{1.30}$
= 15.03+15.38
= 30.41 cm.