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Standard XII

Physics

Atmospheric Pressure

A vessel has ...

Question

A vessel has a small hole at its bottom. If water can be poured into it upto a height of $7 c m$ without leakage ( $g = 10 m s^{- 2}$ ), the radius of the hole is (surface tension of water is $0.07 N m^{- 1}$ ).

2 m m

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0.2 m m

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0.1 m m

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0.4 m m

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Solution

The correct option is B $0.2 m m$
Surface tension can hold wt of $7 c m$ of water above it.
$T = \frac{r h ρ g}{2} \Rightarrow r = \frac{2 T}{h ρ g}$

$r = \frac{0.07 \times 2}{0.07 \times 1000 \times 10}$
$r = 2 \times 10^{- 4} m$
$= 0.2 m m$

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A vessel has a small hole at its bottom. If water can be poured into it upto a height of 7cm without leakage (g=10ms−2), the radius of the hole is (surface tension of water is 0.07Nm−1).

The correct option is B 0.2 mmSurface tension can hold wt of 7cm of water above it.T=rhρg2⇒r=2Thρgr=0.07×20.07×1000×10r=2×10−4m=0.2mm

A vessel has a small hole at its bottom. If water can be poured into it upto a height of $7 c m$ without leakage ( $g = 10 m s^{- 2}$ ), the radius of the hole is (surface tension of water is $0.07 N m^{- 1}$ ).

The correct option is B $0.2 m m$
Surface tension can hold wt of $7 c m$ of water above it.
$T = \frac{r h ρ g}{2} \Rightarrow r = \frac{2 T}{h ρ g}$

$r = \frac{0.07 \times 2}{0.07 \times 1000 \times 10}$
$r = 2 \times 10^{- 4} m$
$= 0.2 m m$