A vessel in the shape of a cuboid contains some water. If three identical spheres are immersed in the water, the level of water is increased by 2 cm. If the area of the base of the cuboid is 160 cm2 and its height 12 cm, determine the radius of any of the spheres.
Area of the base of the cuboid = 160 cm²
Let the radius of the sphere be r cm.
Volume of three spheres =4πr3 [3 times volume of single sphere]
Increased height of the cuboidal vessel = 2 cm
Increased volume of the water =160×2=320 cm3
Since the volume is increased after immersing the 3 spheres in the vessel, increased volume of water will be equal to the volume of three spheres.
=>4πr3=320
=>r3=25.45
=>r=2.94 cm
Thus, the radius of the spheres is 2.94 cm.