Question

A vessel is filled with a liquid of relative density (R.D) = 1.25 as shown

B is 80 cm below and 50 cm to the left of point A. What will be the pressure difference (in kPa) between the two points A and B

• A. 12.5
• B. 8
• C. 125
• D. 10

Answer 1

The correct option is D 10

Pressure intensity of liquids in the vertical downward direction increases, but remains constant in the horizontal direction. Thus, $P_B=\rho gh+P_A$

where;

$P_B=pressureatB\left(N/m^2\right)$
$P_A=pressureatA\left(N/m^2\right)$

$\rho =\text{mass density of the liquid}\left(kg/m^3\right)$

$\rho =1250kg/m^3$

$g=$ Acceleration due to gravity

$=10m/se{c}^2$ (Assumed)

h = Vertical distance separating the two point A and B

$h=0.8m$

$\therefore P_B-P_A=\rho gh=1250\times 10\times 0.8=10000N/m^2=10kPa$