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Standard X

Physics

Ideal Gas Equation

A vessel is f...

Question

A vessel is filled with an ideal gas at a pressure of 10 atm and temperature $27^{o}$ C. Half of the mass is removed from the vessel and temperature of the remaining gas is increased to $87^{o}$ C. Then the pressure of the gas in the vessel will be

5 atm

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6 atm

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7 atm

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8 atm

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Solution

The correct option is A 6 atm
Using ideal gas law, $P V = n R T$
$⟹ P \propto n T \propto m T$
where $m$ is the mass of the gas inside the vessel.
Thus $\frac{P_{2}}{P_{1}} = \frac{1}{2} . \frac{273 + 87}{273 + 27}$
$⟹ P_{2} = 6 a t m$
Hence correct answer is option B.

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A vessel is filled with an ideal gas at a pressure of 10 atm and temperature 27oC. Half of the mass is removed from the vessel and temperature of the remaining gas is increased to 87oC. Then the pressure of the gas in the vessel will be

The correct option is A 6 atmUsing ideal gas law, PV=nRT⟹P∝nT∝mTwhere m is the mass of the gas inside the vessel.Thus P2P1=12.273+87273+27⟹P2=6atmHence correct answer is option B.

A vessel is filled with an ideal gas at a pressure of 10 atm and temperature $27^{o}$ C. Half of the mass is removed from the vessel and temperature of the remaining gas is increased to $87^{o}$ C. Then the pressure of the gas in the vessel will be

The correct option is A 6 atm
Using ideal gas law, $P V = n R T$
$⟹ P \propto n T \propto m T$
where $m$ is the mass of the gas inside the vessel.
Thus $\frac{P_{2}}{P_{1}} = \frac{1}{2} . \frac{273 + 87}{273 + 27}$
$⟹ P_{2} = 6 a t m$
Hence correct answer is option B.