A vessel is filled with an ideal gas at a pressure of $20$ atm and is at a temperature of $27^{\circ} C$ . One-half of the mass is removed from the vessel and the temperature of the remaining gas is increased to $87^{\circ} C$ . At this temperature find the pressure of the gas.

Open in App

Solution

Since the volume of gas is kept constant,

$\frac{P}{n T} = c o n s t a n t$

$\frac{20}{n (300)} = \frac{P}{0.5 n (360)}$

$P = 12 a t m$

Answer is $12 a t m$ .

Suggest Corrections

Similar questions

Q. A vessel is filled with an ideal gas at a pressure of

10

atm and temperature

27^{\circ} C

. Half of the mass is removed from the vessel and temperature of the remaining gas is increased to

87^{\circ} C

. Then the pressure of the gas in the vessel will be:

Q. A vessel is filled with an ideal gas at a pressure of 10 atm and temperature

27^{o}

C. Half of the mass is removed from the vessel and temperature of the remaining gas is increased to

87^{o}

C. Then the pressure of the gas in the vessel will be

Q. A vessel is filled with an ideal gas at a pressure of

10 atm

and temperature of

27^{\circ} C

. Half of the mass is removed from the vessel and temperature of the remaining gas is increased to

87^{\circ} C

. Then the pressure of the gas in the vessel will be

A vessel is filled with an ideal gas at a pressure of 10 atmospheres and temp 27 $^{0}$ C . Half of the mass of the gas is removed from the vessel & the temp. of the remaining gas is increased to 87 $^{0}$ C . Then the pressure of the gas in the vessel will be

Q. The gas in a vessel in subjected to a pressure of

20

atmosphere at a temperature

27^{\circ} C

. The pressure of the gas in the vessel after one half of the gas is released from the vessel and the temperature of the remainder is raised by

50^{\circ} C

, is

Join BYJU'S Learning Program

A vessel is filled with an ideal gas at a pressure of 20 atm and is at a temperature of 27∘C. One-half of the mass is removed from the vessel and the temperature of the remaining gas is increased to 87∘C. At this temperature find the pressure of the gas.

Since the volume of gas is kept constant,PnT=constant20n(300)=P0.5n(360)P=12atmAnswer is 12atm.

A vessel is filled with an ideal gas at a pressure of $20$ atm and is at a temperature of $27^{\circ} C$ . One-half of the mass is removed from the vessel and the temperature of the remaining gas is increased to $87^{\circ} C$ . At this temperature find the pressure of the gas.

Since the volume of gas is kept constant,

$\frac{P}{n T} = c o n s t a n t$

$\frac{20}{n (300)} = \frac{P}{0.5 n (360)}$

$P = 12 a t m$

Answer is $12 a t m$ .