A vessel of area of cross-section A has liquid upto a height H. A hole is made in the wall of vessel such that water coming out of it travels maximum horizontal distance of 2m. Find the value of H.
A
2m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A2m We know,
Horizontal range of liquid coming out of hole R=2√h(H−h)
For maximum range, h=H2 where H is height upto which liquid stands.
Given, Rmax=2m ∴2=2√H2(H−H2) ⇒H=2m