Question

A vessel of area of cross-section $A$ has liquid upto a height $H$. A hole is made in the wall of vessel such that water coming out of it travels maximum horizontal distance of $2\text{m}$. Find the value of $H$.

• A. $2\text{m}$
• B. $1\text{m}$
• C. $3\text{m}$
• D. $4\text{m}$

Answer 1

The correct option is A $2\text{m}$

We know,
Horizontal range of liquid coming out of hole $R=2\sqrt{h(H-h)}$
For maximum range, $h=\frac{H}{2}$ where $H$ is height upto which liquid stands.
Given, $R_{max}=2\text{m}$
$\therefore 2=2\sqrt{\frac{H}{2}(H-\frac{H}{2})}$
$\Rightarrow H=2\text{m}$