A vessel of capacity 600 cm3 contains hydrogen gas at a pressure 330 cm Hg .what will be the pressure of hydrogen gas when the vessel is connected to another vessel of 300 cm3 capacity

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Solution

Dear student,
As per the Boyle's Law , P₁V₁ = P₂V₂
330 X 600 = P X ( 600 + 300)
P = 220 cmHg
Regards

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A vessel of capacity 600 cm3 contains hydrogen gas at a pressure 330 cm Hg .what will be the pressure of hydrogen gas when the vessel is connected to another vessel of 300 cm3 capacity

Dear student, As per the Boyle's Law , P1V1 = P2V2 330 X 600 = P X ( 600 + 300) P = 220 cmHg Regards

Dear student,
As per the Boyle's Law , P₁V₁ = P₂V₂
330 X 600 = P X ( 600 + 300)
P = 220 cmHg
Regards