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Question

A vessel of depth 2d is half filled with a liquid of refractive index μ1 and the upper-half with a liquid of refractive index μ2 . The apparent depth of the vessel seen perpendicular is

A
d(μ1μ2μ1+μ2)
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B
d(1μ1+1μ2)
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C
2d(1μ1+1μ2)
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D
2d(1μ1μ2)
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Solution

The correct option is D d(1μ1+1μ2)
Apparent depth =real depthrefractive index

depth seen =dμ1+dμ2

=d(1μ1+1μ2)

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