Question

A vessel of height $H$ and length $L$ contains a liquid of density $\rho$ upto height $H/2$. The vessel starts accelerating horizontally with acceleration ${}^{\prime }{a}^{\prime }$ towards right. If $A$ is the point at the surface of the liquid at right end while the vessel is accelerating and $B$ is the point at bottom of the vessel on the other end, the difference of pressures at $B$ and $A$ will be

Answer 1

$P_A-P_C=eg\frac{H}{2}(P_B-P_C)\frac{H}{2}L=e\frac{H}{2}{L}^2.a\Rightarrow P_B-P_c=eLa\therefore P_A-P_B=eg\frac{H}{2}-eLa$