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Standard XII

Chemistry

Stoichiometry

A vessel of o...

Question

A vessel of one litre capacity containing $1$ mole of ${S O}_{3}$ is heated till a state of equilibrium is attained.
$2 {S O}_{3 (g)} ⇌ 2 {S O}_{2 (g)} + O_{2 (g)}$
At equilibrium, $0.6$ moles of ${S O}_{2}$ had formed. The value of equilibrium constant is:

0.18

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0.36

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0.45

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0.68

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Solution

The correct option is D $0.68$
$2 {S O}_{3 (g)} ⇌ 2 {S O}_{2 (g)} + O_{2 (g)}$

Initial conc. $1.0$ mole $0.0$ mole $0.0$ mole
Equilibrium $0.4$ mole $0.6$ mole $0.3$ mole

$\Rightarrow$ Equilibrium constant is given by

$K = \frac{{[{S O}_{2}]}^{2} [O_{2}]}{{[{S O}_{3}]}^{2}} = \frac{{(0.6)}^{2} (0.3)}{{(0.4)}^{2}} = 0.675 = 0.68$

Hence, the correct option is $D$

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Similar questions

Q. One mole of

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2 S O_{3} (g) ⇌ 2 S O_{2} (g) + O_{2} (g)

At equilibrium,

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Q. The equilibrium constant for the reaction:

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Q. One mole of

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A vessel of one litre capacity containing 1 mole of SO3 is heated till a state of equilibrium is attained.2SO3(g)⇌2SO2(g)+O2(g)At equilibrium, 0.6 moles of SO2 had formed. The value of equilibrium constant is:

The correct option is D 0.68 2SO3(g)⇌2SO2(g)+O2(g)Initial conc. 1.0 mole 0.0mole 0.0moleEquilibrium 0.4 mole 0.6 mole 0.3mole⇒ Equilibrium constant is given byK=[SO2]2[O2][SO3]2=(0.6)2(0.3)(0.4)2=0.675=0.68Hence, the correct option is D

A vessel of one litre capacity containing $1$ mole of ${S O}_{3}$ is heated till a state of equilibrium is attained.
$2 {S O}_{3 (g)} ⇌ 2 {S O}_{2 (g)} + O_{2 (g)}$
At equilibrium, $0.6$ moles of ${S O}_{2}$ had formed. The value of equilibrium constant is: