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Question
A vessel of uniform cross-section of length 500 cm as shown in figure is divided in two parts by a weightless and frictionless piston.One part contains 5 moles of He(g) and other part contains 2 moles of H2(g) and 4 mole of O2(g) added at the same temperature are pressure in which reaction takes place finally and vessel cooled to 300 K and 1 atm. What is the length of He compartment? (Assume volume of piston and volume of H2O(l) formed are negligible)
A vessel of uniform cross-section of length 500 cm as shown in figure is divided in two parts by a weightless and frictionless piston.One part contains 5 moles of He(g) and other part contains 2 moles of H2(g) and 4 mole of O2(g) added at the same temperature are pressure in which reaction takes place finally and vessel cooled to 300 K and 1 atm. What is the length of He compartment? (Assume volume of piston and volume of H2O(l) formed are negligible)
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Solution
The correct option is C 312.5 cm
Moles of O2 remaining after reaction = 4-1 = 3
V ∝ n is due to same T and P in each compartment after reaction.
∴ Length of He compartment = 55+3×500 = 312.5 cm
312.5 cm
Moles of O2 remaining after reaction = 4-1 = 3
V ∝ n is due to same T and P in each compartment after reaction.
∴ Length of He compartment = 55+3×500 = 312.5 cm
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