Question

A vessel of volume $0.02m^3$ contains a mixture of hydrogen and helium at ${20}^{\circ }C$ and 2 atmospheric pressure. The mass of mixture is 5 gms. The ratio of mass of hydrogen to that of helium in the mixture is x:y.
so x+y is........

Answer 1

From ideal gas equation $PV=nRT$,
Here, assume mass of helium in mixture is x, then mass of hydrogen is (5-x) so, $2\times {10}^5\times 0.02=\left(\right(5-x)/2+x/4)8.314\times 293$.
$x=3.43and5-x=1.57$.
So ratio of hydrogen to helium is 1:2.
then x+ y = 3