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Standard XII

Physics

Carnot Cycle

A vessel of v...

Question

A vessel of volume $0.2 m^{3}$ contain $H_{2}$ gas $(C_{v} = 5 c a l m o l^{- 1} K^{- 1})$ at 300 K and 1 atm P. The heat required to raise the temperature to 400 K is:

4 kcal

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2 kcal

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6 kcal

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8 kcal

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Solution

The correct option is A 4 kcal
As we know,
$Q_{v} = n \times C_{v} \times d T$

and by ideal gas equation,
$n = \frac{P V}{R T} = \frac{1 \times 0.2 \times 10^{3}}{0.0821 \times 300}$

$Q_{v} = n \times C_{v} \times d T$
$= n \times 5 \times 100$
$= 4.06 \times 10^{3} c a l$

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A vessel of volume 0.2m3 contain H2 gas (Cv=5calmol−1K−1) at 300 K and 1 atm P. The heat required to raise the temperature to 400 K is:

The correct option is A 4 kcalAs we know,Qv=n×Cv×dTand by ideal gas equation,n=PVRT=1×0.2×1030.0821×300Qv=n×Cv×dT=n×5×100=4.06×103cal

A vessel of volume $0.2 m^{3}$ contain $H_{2}$ gas $(C_{v} = 5 c a l m o l^{- 1} K^{- 1})$ at 300 K and 1 atm P. The heat required to raise the temperature to 400 K is:

The correct option is A 4 kcal
As we know,
$Q_{v} = n \times C_{v} \times d T$

and by ideal gas equation,
$n = \frac{P V}{R T} = \frac{1 \times 0.2 \times 10^{3}}{0.0821 \times 300}$

$Q_{v} = n \times C_{v} \times d T$
$= n \times 5 \times 100$
$= 4.06 \times 10^{3} c a l$