You visited us 4 times! Enjoying our articles? Unlock Full Access!

Heat of Reaction

A vessel of v...

Question

A vessel of volume $0.2 m^{3}$ contains hydrogen gas at temperature $300 K$ and pressure $1 b a r$ . Find the heat (in kcal) required to raise the temperature to $400 K$ . (The molar heat capacity of hydrogen at constant volume is $5 c a l / m o l K$ )

4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $4$
Using the equation $P V = n R T$ we have
$0.2 \times 10^{5} = n \times 8.314 \times 300$
Thus we get n as 8 moles.
Now the heat absorbed is given as
$Q = W + U = n R Δ T + n C_{v} Δ T$
or
$Q = n (1 + \frac{3}{2}) R Δ T$
or
$Q = 8 \times \frac{5}{2} \times 1.987 \times 100 = 4000 k c a l$

Suggest Corrections

Similar questions

0.2 m^{3}

300 K

1 b a r

400 K

5 c a l / m o l K

0.2 m^{3}

H e

300 K

10^{5} {N/m}^{2}

400 K

H e

5 {cal K}^{- 1} {mol}^{- 1}

5 c a l / m o l^{o} C

H_{2}

10^{o} C

0.2 m^{3}

H e

300 K

10^{5} {N/m}^{2}

400 K

H e

5 {cal K}^{- 1} {mol}^{- 1}

0.2 m^{3}

H_{2}

(C_{v} = 5 c a l m o l^{- 1} K^{- 1})

Join BYJU'S Learning Program