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Ideal Gas Equation

A vessel of v...

Question

A vessel of volume 5 litres contains 1.4 g of $N_{2}$ and 0.4 g of He at 1500 K. If 30% of the nitrogen molecules are dissociated into atoms then find the gas pressure.

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Solution

After dissolution, total moles will be $0.7 n + 2 (0.3) n = 1.3 n$ where n is initial moles of nitrogen. Hence,

$P (5 X 10^{- 3}) = (\frac{0.4}{4} + 1.3 \frac{1.4}{28}) (8.314) (1500)$

$P = \frac{0.165 X 8.314 X 1500}{5 X 10^{- 3}} = 4.1 X 10^{5} P a$

Answer is $4.1 X 10^{5} P a$

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