A vessel of volume $8.0 \times 10^{- 3} m^{3}$ contains an ideal gas at 300k and 200k Pa. The gas is allowed to leak till the pressure falls to 125 k Pa. Calculate the amount of gas (in moles) leaked assuming that the temperature remains constant.

0.24 moles

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0.34 moles

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0.44 moles

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0.54 moles

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Solution

The correct option is A 0.24 moles
Temperature and volume are constants.
$n = \frac{P V}{R T} o r n_{i} = \frac{P_{i} V}{R T} a n d n_{f} = \frac{P_{f} V}{R T}$
Amount leaked $= n_{i} - n_{f} = \frac{(P_{i} - P_{f}) V}{R T}$
$= \frac{(200 - 125) \times 10^{3} \times (8.0 \times 10^{- 3})}{8.31 \times 300} = 0.24 m o l e s$

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A vessel of volume 8.0×10−3m3 contains an ideal gas at 300k and 200k Pa. The gas is allowed to leak till the pressure falls to 125 k Pa. Calculate the amount of gas (in moles) leaked assuming that the temperature remains constant.

The correct option is A 0.24 molesTemperature and volume are constants. n=PVRTorni=PiVRTandnf=PfVRT Amount leaked =ni−nf=(Pi−Pf)VRT =(200−125)×103×(8.0×10−3)8.31×300=0.24 moles

A vessel of volume $8.0 \times 10^{- 3} m^{3}$ contains an ideal gas at 300k and 200k Pa. The gas is allowed to leak till the pressure falls to 125 k Pa. Calculate the amount of gas (in moles) leaked assuming that the temperature remains constant.