A vessel of volume V contains $n_{1}$ moles of oxygen and $n_{2}$ moles of carbon dioxide at absolute temperature T. The pressure of the mixture is

\frac{(n_{1} + n_{2}) R T}{V}

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\frac{(n_{1} - n_{2}) R T}{V}

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\frac{n_{1} n_{2} R T}{V}

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\frac{n_{1} R T}{n_{2} V}

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Solution

The correct option is D $\frac{(n_{1} + n_{2}) R T}{V}$
$p a r t i a l p r e s s u r e d u e t o n_{1} (_{1} = \frac{n_{1} R T}{V}) S i m i l a r l y d u e t o n_{2} (_{2} = \frac{n_{2} R T}{V}) t o t a l p r e s s u r e P =_{1} +_{2} P = \frac{(n_{1} {+ n}_{2}) R T}{V}$

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A vessel of volume V contains n1 moles of oxygen and n2 moles of carbon dioxide at absolute temperature T. The pressure of the mixture is

The correct option is D (n1+n2)RTVpartialpressuredueton1(∙P1=n1RTV)Similarlydueton2(∙P2=n2RTV)totalpressureP=∙P1+∙P2P=(n1+n2)RTV

A vessel of volume V contains $n_{1}$ moles of oxygen and $n_{2}$ moles of carbon dioxide at absolute temperature T. The pressure of the mixture is

The correct option is D $\frac{(n_{1} + n_{2}) R T}{V}$
$p a r t i a l p r e s s u r e d u e t o n_{1} (_{1} = \frac{n_{1} R T}{V}) S i m i l a r l y d u e t o n_{2} (_{2} = \frac{n_{2} R T}{V}) t o t a l p r e s s u r e P =_{1} +_{2} P = \frac{(n_{1} {+ n}_{2}) R T}{V}$