A vibrating magnetometer consists to two identical bar magnets placed one over the other such that they are perpendicular and bisect each other. The time period of oscillation in a horizontal magnetic field is $2^{5 / 4}$ sec. If one of the magnets is removed and the other magnet oscillates in the same field, then the time period in seconds will be

2^{1 / 4}

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2^{1 / 2}

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2

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2^{3 / 4}

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Solution

The correct option is C $2$

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