A vibrating system is analysed and it is found that two successive oscillations have amplitudes of 3 mm and 0.5 mm respectively. Calculate the damping ratio.
A
0.274
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B
0.256
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C
0.263
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D
0.292
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Solution
The correct option is A0.274 For successive amplitudes m=1 Amplitude reduction factor =ln(x1x2)=ln(30.5)=ln6=1.792 Amplitude reduction factor =2πδm√1−δ2 ⇒2πδm√1−δ2=1.792 squaring both sides 39.478δ21−δ2=3.21⇒δ2=0.075⇒δ=0.274