A vibrating tuning fork is moving slowly and uniformly in a horizontal circular path of radius 8 m. The shortest distance of an observer in same plane from the tuning fork is 9 m. The distance between the tuning fork and observer at the instant when apparent frequency becomes maximum is

9 m

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25 m

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15 m

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\sqrt{353}

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Solution

The correct option is C 15 m
$\begin{matrix} O F = \sqrt{{(17)}^{2} - {(8)}^{2}} = \sqrt{289 - 64} = \sqrt{225} = 15 m \end{matrix}$
Hence,
option $(C)$ is correct answer.

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A vibrating tuning fork is moving slowly and uniformly in a horizontal circular path of radius 8 m. The shortest distance of an observer in same plane from the tuning fork is 9 m. The distance between the tuning fork and observer at the instant when apparent frequency becomes maximum is

The correct option is C 15 mOF=√(17)2−(8)2=√289−64=√225=15mHence,option (C) is correct answer.

The correct option is C 15 m
$\begin{matrix} O F = \sqrt{{(17)}^{2} - {(8)}^{2}} = \sqrt{289 - 64} = \sqrt{225} = 15 m \end{matrix}$
Hence,
option $(C)$ is correct answer.