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Question
A vibrating tuning fork is placed close to another of equal frequency. The other also starts vibrating. This happens because of
A vibrating tuning fork is placed close to another of equal frequency. The other also starts vibrating. This happens because of
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Solution
The correct option is A resonance
When the body oscillates with its own natural frequency due to some external periodic force whose frequency is equal to(or in integral multiple of) the natural frequency of vibrating body, the oscillations of such vibrating body with large amplitude is known as resonance.
Hence, when a vibrating tuning fork is placed close to another of equal frequency, the other also starts vibrating due to resonance.
While interference, superposition happens due to interaction or overlapping of two or more waves and formation of standing waves takes place due to similar waves travelling in opposite directions.
When the body oscillates with its own natural frequency due to some external periodic force whose frequency is equal to(or in integral multiple of) the natural frequency of vibrating body, the oscillations of such vibrating body with large amplitude is known as resonance.
Hence, when a vibrating tuning fork is placed close to another of equal frequency, the other also starts vibrating due to resonance.
While interference, superposition happens due to interaction or overlapping of two or more waves and formation of standing waves takes place due to similar waves travelling in opposite directions.
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