A vibratory motion is represented by x - 2A cos - t - A cos - t - -2- - A cos - t - - - A-2 cos - t - 3 -2-The resultant amplitude of the motion is

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Oscillations

A vibratory m...

Question

A vibratory motion is represented by
$x = 2 A c o s ω t + A c o s [ω t + \frac{π}{2}] + A c o s (ω t + π) + \frac{A}{2} c o s [ω t + \frac{3 π}{2}]$ .
The resultant amplitude of the motion is

\frac{9 A}{2}

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\frac{\sqrt{5} A}{2}

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\frac{5}{2} A

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2 A

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Solution

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Similar questions

y = A \sin^{2} (k x - ω t)

ω / 2 π

ω / π

ω / 4 π

x = A cos ω t + \frac{A}{2} cos (ω t + \frac{π}{2}) + \frac{A}{4} cos (ω t + π) + \frac{A}{8} cos (ω t + \frac{3 π}{2})

x = A cos ω t + \frac{A}{2} cos (ω t + \frac{π}{2}) + \frac{A}{4} cos (ω t + π) + \frac{A}{8} cos (ω t + \frac{3 π}{2})

y_{1} = 4 sin (4 π t - \frac{π}{2})

y_{2} = 3 cos (4 π t) .

-

x -

A, ω

k

x = \frac{λ}{4}

y (t) = A sin ω t

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