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Question

A violet compound of magnese A decomposes on heating to liberate an oxygen and compounds B and C of magnese are formed .compound C reacts with KOH in presence of potassium nitrate to give compound B .On heating compound C with H2So4 and NaCl, chlorine gas is liberated and compound D of magnese along with other product is formed.Identify compound A to D and also explain the reaction involved.

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Solution

The compound (C) on treating with conc. H2S04 and NaCl gives Cl2 gas, so it is manganese dioxide (MnO2). It is obtained along with when MnO42- when KMnO4 (violet) is heated.

Thus, (A) = KMnO4
(B) = K2MnO4

(C) = MnO2
(D) = MnCl2

KMnO4 K2MnO4 + MnO2 + O2
A B C

2MnO4 + 4KOH + O2 → 2K2MnO4 + 2H2O

MnO2 + 4NaCl + 4H2SO4 → MnCl2 + 4NaHSO4 + 2H2O + Cl2
D


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