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First Order Reaction

A viral prepa...

Question

A viral preparation was inactivated in a chemical bath. The inactivation process was found to be of first-order in virus concentration, and at the beginning of the experiment $2.0$ % of the virus was found to be inactivated per minute. Evaluate ' $k$ ' for the inactivation process.

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Solution

$a = 100$ , $a - x = 98$ , $t = 60$ sec
$k = \frac{2.303}{t} {log}_{10} (\frac{a}{a - x})$
$= \frac{2.303}{60} {log}_{10} (\frac{100}{98}) = 3.3 \times 10^{- 4} {s e c}^{- 1}$

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