Question

A virtual image is cast by a lens. So, its magnification would be:

• A. Positive
• B. Negative
• C. Zero
• D. Unity

Answer 1

The correct option is A Positive

We know that a real image is always inverted while a virtual is always erect.
Also, magnification (m) is equal to ,
$m=\frac{h_i}{h_o}=-\frac{v}{u}$
If the image is virtual it must be erect so $h_i$ would be along positve y-axis and so does the object height $h_o$.
As, both the image and object height is postive magnification would be positive.