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Standard XII

Physics

FM & PM

A voice signa...

Question

A voice signal of frequency $1000 H z$ and peak voltage of $5.5 V$ is modulated by a carrier of frequency $2 M H z$ and peak voltage of $11 V$ . Then modulation index and lowest frequency in modulated signal is

0.5,

1999 k H z

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1999 k H z

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0.3,

2001 k H z

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0.5,

2001 k H z

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Solution

The correct option is A 0.5, $1999 k H z$
$H = \frac{A_{m}}{A_{c}} = \frac{V_{m}}{V_{c}} = \frac{5.5}{11} = 0.5 w_{l o w e s t} = 2000 k H z - 1 k H z = 1999 k H z$

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A voice signal of frequency 1000 Hz and peak voltage of 5.5 V is modulated by a carrier of frequency 2 MHz and peak voltage of 11 V. Then modulation index and lowest frequency in modulated signal is

The correct option is A 0.5, 1999 kHzH=AmAc=VmVc=5.511=0.5wlowest=2000 kHz−1 kHz=1999 kHz

A voice signal of frequency $1000 H z$ and peak voltage of $5.5 V$ is modulated by a carrier of frequency $2 M H z$ and peak voltage of $11 V$ . Then modulation index and lowest frequency in modulated signal is

The correct option is A 0.5, $1999 k H z$
$H = \frac{A_{m}}{A_{c}} = \frac{V_{m}}{V_{c}} = \frac{5.5}{11} = 0.5 w_{l o w e s t} = 2000 k H z - 1 k H z = 1999 k H z$