Question

# A voltage of peak value 283 V and varying frequency is applied to a series L−C−R combination in which R=3 Ω;L=25 mH and C=400 μF. Then, the frequency (in Hz) of the source at which maximum power is dissipated in the above, is51.650.751.150.3

Solution

## The correct option is D 50.3Given V0=283 V              R=3 Ω L=25×10−3 H     C=400×10−6 F For maximum power XL=XC ωC=1ωL⇒ω2=1LC ω=1√LC f=ω2π=12π√LC =12×3.14×1√25×10−3×400×10−6=50.3

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