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Standard XII

Physics

Ammeter

A voltmeter c...

Question

A voltmeter coil has resistance $50.0 Ω$ and a resistor of $1.15 k Ω$ is connected in series, It can read potential difference an ammeter which $12 v o l t s$ . If this same coil is used to construct an ammeter which can measure currents up to $2.0 A$ , what should be the resistance of the shunt used?

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Solution

$R_{e f f} = (1150 + 50) Ω = 1200 Ω$

$i = (12 / 1200) A = 0.01 A$ .

(The resistor of $50 Ω$ can tolerate)
Let $R$ be the resistance of sheet used.
The potential across both the resistors is same.
$0.01 \times 50 = 1.99 \times R$

$\Rightarrow R = \frac{0.01 \times 50}{1.99} = \frac{50}{199} = 0.251 Ω$

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A voltmeter coil has resistance 50.0Ω and a resistor of 1.15 kΩ is connected in series, It can read potential difference an ammeter which 12volts. If this same coil is used to construct an ammeter which can measure currents up to 2.0A, what should be the resistance of the shunt used?

Reff=(1150+50)Ω=1200Ωi=(12/1200)A=0.01A.(The resistor of 50Ω can tolerate)Let R be the resistance of sheet used.The potential across both the resistors is same.0.01×50=1.99×R⇒R=0.01×501.99=50199=0.251Ω