A voltmeter consists of a 25 Ω coil connected in series with a 575 Ω resistor. The coil takes 10 mA for full-scale deflection. What maximum potential difference can be measured by this voltmeter?

Open in App

Solution

It is given that for maximum current, i = 10 mA, the potential drop across the voltmeter will be maximum.
The effective resistance of the circuit,
$R_{eff} = (575 + 25) Ω = 600 Ω$
The maximum value of potential difference measured,
V = R_eff × i
= 600 × 10 × 10⁻³ = 6 V

Suggest Corrections

Similar questions

Q. A voltmeter has a

25 Ω

coil and

575 Ω

in series. The coil takes 10mA for full scale deflection. The maximum potential difference which can be measured is

A voltmeter consists of a 25 ft coil connected in series with a 575 ft resistor. The coil takes 10 mA for full scale deflection. What maximum potential difference can be measured on this voltmeter?

A galvanometer coil has a resistance $90 Ω$ and full scale deflection current 10mA. A $910 Ω$ resistance is connected in series with the galvanometer to make a voltmeter. If the least count of the voltmeter is $0.1 V$ , the number of divisions on its scale is

Q. A moving coil instrument having a resistance of

10 Ω

, gives a full-scale deflection when the current is 10 mA. What should be the value of the series resistance, so that it can be used as a voltmeter for measuring potential difference up to 100 V?

Q. The resistance of a voltmeter is

180 Ω

. When there is

5 V

potential difference across its ends, it gives full scale deflection. What resistance should be connected in series to obtain a full scale deflection at

25 V

Join BYJU'S Learning Program

A voltmeter consists of a 25 Ω coil connected in series with a 575 Ω resistor. The coil takes 10 mA for full-scale deflection. What maximum potential difference can be measured by this voltmeter?

It is given that for maximum current, i = 10 mA, the potential drop across the voltmeter will be maximum. The effective resistance of the circuit, Reff=575+25 Ω=600 Ω The maximum value of potential difference measured, V = Reff × i = 600 × 10 × 10−3 = 6 V

It is given that for maximum current, i = 10 mA, the potential drop across the voltmeter will be maximum.
The effective resistance of the circuit,
$R_{eff} = (575 + 25) Ω = 600 Ω$
The maximum value of potential difference measured,
V = R_eff × i
= 600 × 10 × 10⁻³ = 6 V