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Question

A voltmeter has a 25Ω coil and 575Ω in series. The coil takes 10mA for full scale deflection. The maximum potential difference which can be measured is

A
250mV
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B
5.75V
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C
5.5V
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D
6.0V
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Solution

The correct option is D 6.0V
Let, resistance of voltmeter is, Rv=25Ω
resistance of coil is, Rc=575Ω
Current is I=10mA=10×103A
Since, a voltmeter and a coil are connected in series, same current flow through both of them.
According to KVL.
IRv+IRcV=0
V=I(Rv+Rc)
V=10×103(25+575)
V=600×102
V=6V

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