The correct option is B (n−1)G
Let R be the resistance to be connected in series to convert galvanometer into voltmeter.
Hence,
R=VIg−G
where, Ig is the current through galvanometer.
The voltmeter gives the full-scale deflection for potential difference V. Its resistance is G. Hence, Ig=VG.
Given that V=nV.
Therefore,
R=nV(VG)−G=(n−1)G