Question

A voltmeter having resistance of $50\times {10}^3\Omega$ is used to measure the voltage in the circuit. To increase the range of measurement $3$ times the additional series resistance required is.

• A. ${10}^5\Omega$
• B. $150k\Omega$
• C. $900k\Omega$
• D. $9\times {10}^6\Omega$

Answer 1

The correct option is A ${10}^5\Omega$

We know that the formula for calculating the resistance in voltmeter is given by;

$R=G(n-1)$

$R=50\times {10}^3(3-1)$

$R={10}^5\Omega$